Matematika Sekolah Menengah Pertama sederhanakan pecahan berikut!​

sederhanakan pecahan berikut!​

Nomor 1

[tex] \frac{20}{50} = \frac{20 : 10}{50 : 10} = \bf\frac{2}{5} [/tex]

Nomor 2

[tex] \frac{18}{36} = \frac{18 : 18}{36 : 18} = \bf\frac{1}{2} [/tex]

Nomor 3

[tex] \frac{30}{90} = \frac{30 : 30}{90 : 30} = \bf \frac{1}{3} [/tex]

Nomor 4

[tex] \frac{10}{200} = \frac{10 : 10}{200 : 10} = \bf \frac{1}{20} [/tex]

Nomor 5

[tex] \frac{14}{42} = \frac{14 : 14}{42 : 14} = \bf \frac{1}{3} [/tex]

Nomor 6

[tex] \frac{12}{46} = \frac{12 : 2}{46 : 2} = \bf \frac{6}{23} [/tex]

Nomor 7

[tex] \frac{15}{35} = \frac{15 : 5}{35 : 5} = \bf \frac{3}{7} [/tex]

Nomor 8

[tex] \frac{9}{54} = \frac{9 : 9}{54 : 9} = \bf \frac{1}{6} [/tex]

Nomor 9

[tex] \frac{7}{28} = \frac{7 : 7}{28 : 7} = \bf \frac{1}{4} [/tex]

Nomor 10

[tex] \frac{5}{15} = \frac{5 : 5}{15 : 5} = \bf \frac{1}{3} [/tex]

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Detail jawaban:

  • Kelas: 3 SD
  • Mapel: Matematika
  • Bab: 7 –Pecahan
  • Kode kategorisasi: 3.2.7

Jawaban:

1.2/5

2.1/2

3.1/3

4.1/20

5.1/3

6.6/23

7.3/7

8.1/6

9.1/4

10.1/3

Penjelasan dengan langkah-langkah:

1.20/50=20/50÷10=2/5

2.18/36=18/36÷18=1/2

3.30/90=30/90÷30=1/3

4.10/200=10/200÷10=1/20

5.14/42=14/42÷14=1/3

6.12/46=12/46÷2=6/23

7.15/35=15/35÷5=3/7

8.9/54=9/54÷9=1/6

9.7/28=7/28÷7=1/4

10.5/15=5/15÷5=1/3

Semoga membantu maaf kalo salah jadikan jawaban terbaik ya terima kasih

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